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(B) The given inequation is $x^2 - 13x - 30 \leq 0$.Factoring the quadratic expression,we get $(x - 15)(x + 2) \leq 0$.For this product to be less tha

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$\frac{3}{20}$

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(B) The given inequation is $x^2 - 13x - 30 \leq 0$.Factoring the quadratic expression,we get $(x - 15)(x + 2) \leq 0$.For this product to be less than or equal to zero,$x$ must lie in the interval $[-2, 15]$.Since $x$ is a natural number $(x \in \mathbb{N})$,the possible values for $x$ are ${1, 2, 3, \dots, 15}$.The total number of natural numbers in the set ${1, 2, \dots, 100}$ is $100$.The number of favorable outcomes is $15$.Therefore,the required probability is $\frac{15}{100} = \frac{3}{20}$.

$A$ natural number is selected at random from the set $\{x \in \mathbb{N} : 1 \leq x \leq 100\}$. The probability that the number satisfies the inequation $x^2 - 13x \leq 30$ is:

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